A particle is dropped from point P at time t = 0. At the same time another particle is thrown from point O as shown in the figure and it collides with the particle P. Acceleration due to gravity is along the negative y-axis. If the two particles collide 2 s after they start, find the initial velocity `v_0` of the particle which was projected from O. Point O is not necessarily on ground.

Options

A. `sqrt6m//s^(-1),theta=tan^(-1)(1)` with X-axis
B. `sqrt26m//s^(-1),theta=tan^(-1)(5)` with X-axis
C. `sqrt2m//s^(-1),theta=tan^(-1)(2)` with X-axis
D. `sqrt13m//s^(-1),theta=tan^(-1)(4)` with X-axis

Answer

B

Explanation

`x=(U cos theta)t=2,U cos theta=1`
`(U sin theta)t-1/2"gt"^(2)=-10 , Usin theta=5`
`V=sqrt((U cos theta)^(2)+(U sin theta)^(2))=sqrt26,Tan theta=5`