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A particle A is projected from the groun...

A particle `A` is projected from the ground with an initial velocity of `10m//s` at an angle of `60^(@)` with horizontal. From what height should an another particle `B` be projected horizontally with velocity `5m//s` so that both the particles collide in ground at point `C` if both are projected simultaneously `g=10 m//s^(2)`.

A

`10 m`

B

`15 m`

C

`20 m`

D

`30 m`

Text Solution

Verified by Experts

The correct Answer is:
B
`t=(2U sin theta)/g=sqrt3 , S=1/2"gt"^(2) h=15m`
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