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A smooth square plateform ABCD is moving...

A smooth square plateform ABCD is moving towards right with a uniform speed v. At what angle `theta` must a particle be projected from A with speed u so that it strikes the point B

A

`sin^(-1)(u/v)`

B

`cos^(-1)(v/u)`

C

`cos^(-1)(u/v)`

D

`sin^(-1)(v/u)`

Text Solution

Verified by Experts

The correct Answer is:
B
Particle will strike the point `B` if velocity of particle with respect to platform is along `AB` or component of its relative velocity along `AD` is zero. i.e.,
`u cos theta=v`
or `theta=cos ^(-1)(v/u)`
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