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The distance between two moving particle...

The distance between two moving particles `P` and `Q` at any time is a.If `v_(r)` be their relative velocity and if `u` and `v` be the components of `v_(r)`, along and perpendicular to `PQ`.The closest distance between `P` and `Q` and time that elapses before they arrive at their nearest distance is

Text Solution

Verified by Experts

The correct Answer is:
C
`t=(AC)/v=(a cos theta)/v because v cos theta=v_(1),t=(32xx2/sqrt5)/(4sqrt5)=2s`
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Knowledge Check

  • The resultant R of P and Q is perpendicular to P. Also |P| = |R|- The angle between P and Q is [tan 45° = 1]

    A
    `(5pi)/4`
    B
    `(7pi)/4`
    C
    `(pi)/4`
    D
    `(3pi)/4`

  • Two particles start moving from the same point along the same straight line. The first moves with constant velocity v and the second with constant acceleration a . During the time that elapses before the sound catches the first, the greatest distance between the particle is.

    A
    `(v^2)/(a)`
    B
    `(v^2)/(2 a)`
    C
    `(2 v^2)/(a)`
    D
    `(v^2)/(4 a)`

  • Two particles are moving with velocities v_(1) and v_2 . Their relative velocity is the maximum, when the angle between their velocities is

    A
    zero
    B
    `pi//4`
    C
    `pi//2`
    D
    `pi`