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The distance between two moving particle...

The distance between two moving particles `P` and `Q` at any time is a.If `v_(r)` be their relative velocity and if `u` and `v` be the components of `v_(r)`, along and perpendicular to `PQ`.The closest distance between `P` and `Q` and time that elapses before they arrive at their nearest distance is

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The correct Answer is:
C
`t=(AC)/v=(a cos theta)/v because v cos theta=v_(1),t=(32xx2/sqrt5)/(4sqrt5)=2s`
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