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A rock is launched upward at 45^(@).A be...

A rock is launched upward at `45^(@)`.A bee moves along the trajectory of the rock at a constant speed equal to the initial speed of the rock.The magnitude of acceleration of the bee at the top point of the trajectory is `xg`?For the rock, neglect the air resistance.Find the value of `x`.

Text Solution

Verified by Experts

The correct Answer is:
B

Acceleration of bee `=u^(2)/Rrarr(1)`
At highest position, `R=(u/sqrt2)^(2)/g=u^(2)/(2g)rarr(2)`
From`(1)&(2)`
`a_(bee)=2g :.x=2`
(`u=`projection speed of rock)
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