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If initial velocity of a body is vecu=2v...

If initial velocity of a body is `vecu=2veci-2vecj+3veck` and the final velocity is `vecv=2veci-4vecj+5veck` and it is changed in time of `10 sec`.Find the acceleration vector?

A

`(3veci-2vecj+2veck)/10`

B

`(-3veci+vecj+2veck)/10`

C

`(-3veci-vec2j+2veck)/10`

D

`(vec-j+veck)/5`

Text Solution

Verified by Experts

The correct Answer is:
D
`veca=(vecv-vecu)/t`
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