Home
Class 11
PHYSICS
A man can swim in still water at a speed...

A man can swim in still water at a speed of `6 kmph` and he has to cross the river and reach just opposite point on the other bank.If the river is flowing at a speed of `3 kmph`,and the width of the river is `2km`, the time taken to cross the river is (in hours)

A

`2/27`

B

`2/sqrt27`

C

`2/3`

D

`2/sqrt45`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of a man swimming across a river with a current, we can break it down into a series of steps: ### Step 1: Understand the Problem The man swims in still water at a speed of 6 km/h. The river flows at a speed of 3 km/h, and the width of the river is 2 km. We need to find the time taken for the man to swim directly across the river to the point directly opposite his starting point. ### Step 2: Set Up the Components The swimmer's velocity can be broken down into two components: - **Vertical Component (Vy)**: This is the component of the swimmer's speed that helps him cross the river. - **Horizontal Component (Vx)**: This is the component of the swimmer's speed that counters the river's current. ### Step 3: Use the Right Triangle Using the Pythagorean theorem, we can find the resultant velocity of the swimmer. The swimmer's speed in still water (6 km/h) and the river's speed (3 km/h) form a right triangle: - Vy = 6 km/h (the swimmer's speed) - Vx = 3 km/h (the river's speed) ### Step 4: Calculate the Vertical Component To find the vertical component of the swimmer's velocity (Vy), we can use the sine function: - \( Vx = 6 \sin(\theta) \) - \( Vx = 3 \) km/h (to counter the river's flow) Thus, we have: \[ 6 \sin(\theta) = 3 \implies \sin(\theta) = \frac{1}{2} \implies \theta = 30^\circ \] Now, we can find the vertical component: \[ Vy = 6 \cos(30^\circ) = 6 \cdot \frac{\sqrt{3}}{2} = 3\sqrt{3} \text{ km/h} \] ### Step 5: Calculate the Time to Cross the River The time taken to cross the river can be calculated using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Velocity}} \] Where: - Distance = 2 km (width of the river) - Velocity = \( Vy = 3\sqrt{3} \) km/h Substituting the values: \[ \text{Time} = \frac{2 \text{ km}}{3\sqrt{3} \text{ km/h}} = \frac{2}{3\sqrt{3}} \text{ hours} \] ### Final Answer The time taken to cross the river is: \[ \text{Time} = \frac{2}{3\sqrt{3}} \text{ hours} \]

To solve the problem of a man swimming across a river with a current, we can break it down into a series of steps: ### Step 1: Understand the Problem The man swims in still water at a speed of 6 km/h. The river flows at a speed of 3 km/h, and the width of the river is 2 km. We need to find the time taken for the man to swim directly across the river to the point directly opposite his starting point. ### Step 2: Set Up the Components The swimmer's velocity can be broken down into two components: - **Vertical Component (Vy)**: This is the component of the swimmer's speed that helps him cross the river. ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    NARAYNA|Exercise Level-II(H.W)|31 Videos
  • MOTION IN A PLANE

    NARAYNA|Exercise Level-Vi Integer|9 Videos
  • MECHANICAL PROPERTIES OF SOLIDS

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Level 2 H.W|29 Videos

Similar Questions

Explore conceptually related problems

A man can swim in still water at a speed of 5km//h . Man crosses 1 km width of river along shortest possible path in 15 minutes . What is the speed of river in km/h?

A man can swim in still water at a speed of 4 kmph . He desires to cross a river flowing at a speed of 3 kmph in the shortest time interval. If the width of the river (in hours) and the horizontal distance travelled (in km) are respectively

A man wishes to cross a river flowing with velocity u swims at an angle theta with the river flow.If the man swims with speed v and if the width of the river is d , then the drift travelled by him is

A man can swim in still water ast a speed of 3 km/h. He wants to cross a river that flows at 2 km/h and reach the point directly oposite to his starting point. A. In which diretionshoeld he try to swim (that is, find the angle his body makes wilth the river flow)? b. How much time will he take to cross the river if the river is 500 m wide?

A man can swim at a speed of 5 km/h W.r.t water. He wants to cross a 1.5 km wide river flowing at 3 km/h. He keeps himself always at an angle of 60° with the flow of direction while swimming, The time taken by him to cross the river will be

A man can swim with speed 5 ms^(-1) in still river while the river is also flowing speed 10ms ^(-1) If the width of the river is 100 m then minimum possible drift is

man wants to swim across a river of which 200 m along the shortest path . If the speed of river stream is 3 km h^(-1) and speed of swimmer in still water is 5 km h^(-1) , then the time of crossing the river is

NARAYNA-MOTION IN A PLANE-Level-I (H.W)
  1. When it is raining vertically down, to a man walking on road the veloc...

    Text Solution

    |

  2. A motor car A is travelling with a velocity of 20m//s in the north-wes...

    Text Solution

    |

  3. A man can swim in still water at a speed of 6 kmph and he has to cross...

    Text Solution

    |

  4. A boat moves perpendicular to the bank with a velocity of 7.2 km//h.Th...

    Text Solution

    |

  5. A swimmer is capable of swimming 1.65 ms^(-1) in still water.If she sw...

    Text Solution

    |

  6. A person swims at 135^(@) to current to river, to meet target on reach...

    Text Solution

    |

  7. The parabolic path of a projectile is represented by y=x/sqrt3-x^(2)/6...

    Text Solution

    |

  8. A body is projected at angle 30^(@) to horizontal with a velocity 50 m...

    Text Solution

    |

  9. A body is projected with velocity 60m//s at 30^(@) to the horizontal.T...

    Text Solution

    |

  10. A body is projected with velocity u such that in horizontal range and ...

    Text Solution

    |

  11. A cricket ball is hit for a six leaving the bat at an angle of 60^(@) ...

    Text Solution

    |

  12. A bomb at rest is exploded and the pieces are scattered in all directi...

    Text Solution

    |

  13. A boy can throw a stone up to a maximum height of 10 m. The maximum h...

    Text Solution

    |

  14. A grass hopper can jump a maximum horizontal distance of 20 .4 cm . I...

    Text Solution

    |

  15. A stone is thrown with a velocity v at an angle theta with the horizon...

    Text Solution

    |

  16. A body is projected with a certain speed at angles of projection of th...

    Text Solution

    |

  17. The launching speed of a certain projectile is five times the speed it...

    Text Solution

    |

  18. A person throws a bottle into a dustbin at the same height as he is 2m...

    Text Solution

    |

  19. A body projected horizontally from the top of a tower follows y=20x^(2...

    Text Solution

    |

  20. A bomb is dropped from an aeroplane flying horizontally with a velocit...

    Text Solution

    |