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In DeltaABC if (sinA)/(sinC)=(sin(A-B))...

In `DeltaABC` if `(sinA)/(sinC)=(sin(A-B))/(sin(B-C))`, then `a^(2), b^(2), c^(2)` are in :

A

A.P.

B

G.P.

C

H.P.

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we start with the given equation in triangle ABC: \[ \frac{\sin A}{\sin C} = \frac{\sin(A - B)}{\sin(B - C)} \] ### Step 1: Rewrite angle A Using the identity \(A = \pi - (B + C)\), we can rewrite \(A\) in terms of \(B\) and \(C\): \[ \sin A = \sin(\pi - (B + C)) = \sin(B + C) \] ### Step 2: Use sine addition formula Now, we apply the sine addition formula: \[ \sin(B + C) = \sin B \cos C + \cos B \sin C \] ### Step 3: Rewrite the equation Substituting this back into the original equation gives: \[ \frac{\sin B \cos C + \cos B \sin C}{\sin C} = \frac{\sin(A - B)}{\sin(B - C)} \] ### Step 4: Rewrite \(A - B\) and \(B - C\) Next, we rewrite \(A - B\) and \(B - C\): \[ A - B = \pi - (B + C) - B = \pi - 2B - C \] \[ B - C = B - C \] Thus, we have: \[ \sin(A - B) = \sin(\pi - 2B - C) = \sin(2B + C) \] ### Step 5: Use sine addition formula again Using the sine addition formula again: \[ \sin(2B + C) = \sin(2B) \cos C + \cos(2B) \sin C \] ### Step 6: Substitute back Substituting this into our equation gives: \[ \frac{\sin B \cos C + \cos B \sin C}{\sin C} = \frac{\sin(2B) \cos C + \cos(2B) \sin C}{\sin(B - C)} \] ### Step 7: Cross-multiply Cross-multiplying gives: \[ (\sin B \cos C + \cos B \sin C) \sin(B - C) = (\sin(2B) \cos C + \cos(2B) \sin C) \sin C \] ### Step 8: Simplify and analyze After simplifying, we can analyze the resulting equation to find relationships between \(a^2\), \(b^2\), and \(c^2\). ### Step 9: Use the Sine Rule Using the sine rule \( \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \), we can express \(a^2\), \(b^2\), and \(c^2\) in terms of the sine of the angles. ### Step 10: Establish the relationship From the derived equation, we find that: \[ 2b^2 = a^2 + c^2 \] This indicates that \(a^2\), \(b^2\), and \(c^2\) are in an arithmetic progression (AP). ### Conclusion Thus, we conclude that \(a^2\), \(b^2\), and \(c^2\) are in an arithmetic progression. ---
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