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In which of the following species, d-obi...

In which of the following species, d-obitals having xz an yz two nodal planes involved in hybridization of central atoms?

A

`IO_(2)F_(2)^(-)`

B

`ClF_(4)^(-)`

C

`IF_(7)`

D

None of these

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The correct Answer is:
To solve the question regarding which species has d-orbitals with xz and yz nodal planes involved in the hybridization of the central atom, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Relevant d-Orbitals**: - The d-orbitals are five in total: \(d_{xy}\), \(d_{xz}\), \(d_{yz}\), \(d_{x^2-y^2}\), and \(d_{z^2}\). - The d-orbital that has both xz and yz as nodal planes is the \(d_{xy}\) orbital. This means that the \(d_{xy}\) orbital is the one we need to focus on. 2. **Analyze the Given Species**: - We need to check the hybridization of the central atom in the given species: \(IF_7\), \(ClF_4^-\), and \(ICl_2^-\). - We will determine the steric number and hybridization for each species. 3. **Determine Hybridization for Each Species**: - **For \(IF_7\)**: - Iodine (I) has 7 valence electrons. - It forms 7 bonds with fluorine atoms (7 sigma bonds). - Steric number = 7 (7 bonds, 0 lone pairs). - Hybridization = \(sp^3d^3\) (involves \(s\), \(p\), and \(d\) orbitals). - The relevant d-orbitals are \(d_{x^2-y^2}\) and \(d_{z^2}\), but not \(d_{xy}\). - **For \(ClF_4^-\)**: - Chlorine (Cl) has 7 valence electrons. - It forms 4 bonds with fluorine and has 2 lone pairs. - Steric number = 6 (4 bonds + 2 lone pairs). - Hybridization = \(sp^3d^2\) (involves \(s\), \(p\), and \(d\) orbitals). - The relevant d-orbitals are \(d_{x^2-y^2}\) and \(d_{z^2}\), but not \(d_{xy}\). - **For \(ICl_2^-\)**: - Iodine (I) has 7 valence electrons. - It forms 2 bonds with chlorine and has 3 lone pairs. - Steric number = 5 (2 bonds + 3 lone pairs). - Hybridization = \(sp^3d\) (involves \(s\), \(p\), and \(d\) orbitals). - The relevant d-orbital is \(d_{xy}\), which does have the required nodal planes. 4. **Conclusion**: - Among the species analyzed, \(ICl_2^-\) is the one where the \(d_{xy}\) orbital is involved in hybridization, which has both xz and yz nodal planes. ### Final Answer: The species in which d-orbitals having xz and yz two nodal planes involved in hybridization of the central atom is **\(ICl_2^-\)**.

To solve the question regarding which species has d-orbitals with xz and yz nodal planes involved in the hybridization of the central atom, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Relevant d-Orbitals**: - The d-orbitals are five in total: \(d_{xy}\), \(d_{xz}\), \(d_{yz}\), \(d_{x^2-y^2}\), and \(d_{z^2}\). - The d-orbital that has both xz and yz as nodal planes is the \(d_{xy}\) orbital. This means that the \(d_{xy}\) orbital is the one we need to focus on. ...
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