IUPAC name of `H_(2)[PtCl_(6)]` is

Options

A. Hydrogen hexachloroplatinate (IV)
B. dihydrogen hexachloroplatinate (IV)
C. hydrogen hexachloroplatinic (IV) acid
D. hexachloroplatinic (IV) acid

Explanation

To determine the IUPAC name of the coordination compound \( H_2[PtCl_6] \), we can follow these steps:

### Step 1: Identify the central metal atom and its oxidation state
The central metal atom in this coordination compound is platinum (Pt). To find its oxidation state, we can set up the following equation based on the overall charge of the complex:

\[ 2(+1) + x + 6(-1) = 0 \]

Where:
- \( 2(+1) \) represents the two hydrogen ions (H) each with a +1 charge.
- \( x \) is the oxidation state of platinum (Pt).
- \( 6(-1) \) represents the six chloride ions (Cl) each with a -1 charge.

Solving the equation:

\[ 2 + x - 6 = 0 \implies x - 4 = 0 \implies x = +4 \]

Thus, the oxidation state of platinum is +4.

### Step 2: Identify the ligands and their names
In the complex \( [PtCl_6]^{2-} \), there are six chloride ions (Cl). The name of the chloride ligand in coordination chemistry is "chloro." Since there are six chloride ligands, we use the prefix "hexa-":

- Ligand: Chloride (Cl)
- Number of ligands: 6
- Name: Hexachloro

### Step 3: Name the coordination complex
The name of the coordination complex is constructed by combining the names of the ligands and the central metal atom. Since the complex ion \( [PtCl_6]^{2-} \) is an anionic complex (due to the overall -2 charge), we use the suffix "-ate" for the metal name. The name of platinum in this case becomes "platinate."

Thus, the name of the complex ion is:

- Hexachloro-platinate

### Step 4: Combine with the counter ions
Since there are two hydrogen ions (H) outside the coordination sphere, we denote them at the beginning of the name. The final IUPAC name of the entire compound is:

- Hydrogen hexachloro-platinate(IV)

### Final Answer
The IUPAC name of \( H_2[PtCl_6] \) is **Hydrogen hexachloro-platinate(IV)**.

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