`FeSO_(4)` is a very good absorber for `NO`, the new compound formed by this process is found to contain number of unpaired electrons:

Options

A. 4
B. 5
C. 3
D. 6

Answer

C

Explanation

`Fe^(3+)(aq)+NO+SO_(4)^(2-)(aq) to [Fe(H_(2)O)_(5)(NO)]^(2+)+SO_(4)^(2-)`
`mu_(e f f)=3.89` BM
Hence, no of unpaired electron=3.