A `[M(H_(2)O)_(6)]^(2+)` complex typically absorbs at around 600 n. it is allowed to react with ammonia to form a new compelx `[M(NH_(3))_(6)]^(2+)` that should have absorption at:

Options

A. 800 nm
B. 580 nm
C. 620 nm
D. 320 nm

Answer

B

Explanation

As `NH_(3)` is sronger ligand than `H_(2)O`, hence CFSE value for `[M(NH_(3))_(6)]^(3+) gt CFSE` of `[M(H_(2)O)_(6)]^(2+)`
therefore, absorption shifts to smaller wavelength. Also difference between splitting power of `NH_(3)` and `H_(2)O` is not very high.