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If the four straight lines ax+by+p=0, ax...

If the four straight lines `ax+by+p=0, ax+by+q=0, cx+dy+r=0` and `cx+dy+s=0` form a prallelogram. Show that the area of the parallelogram so formed is
`|((p-q)(r-s))/(bc-ad)|`

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The correct Answer is:
`:.` Area of the parallelogram `A=(d_(1)d_(2))/(sin theta)=|((p-q)(r-s))/(bc-ad)|`
NA
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