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Find the equation of the plane passing t...

Find the equation of the plane passing through the point (1,2,-3) and parallel to the plane `2x-3y+6z=0`

Text Solution

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The correct Answer is:
`2x-3y+6z+22=0`
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Find the equation of tbe plane passing through the point (1,2,-3) & parallel to the plane 2x-3y+6z=0 .

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Knowledge Check

  • The equation of the plane passing through the point (1, 2, 3) and parallel to xy-plane is

    A
    x+ 2 = 0
    B
    y - 3 = 0
    C
    z = 3
    D
    x - 2 = 0

  • The equation of the plane passing through the point (2,-3,5) and parallel to zx-plane is

    A
    `x+2=0`
    B
    `y+3=0`
    C
    `z-7=0`
    D
    `x-2=0`

  • The equation of the plane passing through the point (-2,-1,-3) and parallel to the plane 2x+y+z-9=0 is

    A
    `2x+y+z+8=0`
    B
    `2x+3y-z-7=0`
    C
    `2x+3y-z-9=0`
    D
    `2x+3y-z+9=0`

    • Similar Questions

    Explore conceptually related problems

    Find the equation of the plane passing through the point (1 ,1 ,1 ) and parallel to the plane x + 2y + 3z - 7 = 0.

    The equation of the plane passing through the point (2,3,-4) and parallel to the plane x+2y+3z-7=0 is

    I: The equation of the plane passing through the point (1, 2, – 3) and parallel to the plane 2x – 3y +z + 5 = 0 is 2x – 3y +z + 7 = 0 II : The equation of the plane passing through the point (1, 2, 3) and parallel to xy-plane is x + 2 = 0

    The equation of the plane passing through the point (1, 2, – 3) and parallel to the plane 2x – 3y +z+5 = 0 is

    The equation of the plane passing through the point (- 1, 2, 4) and parallel to the plane 2x + 3y - 5z + 6 = 0 is

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