The force of attraction between two charges separated by certain distance in air is `F_(1)` .If the space between the charges is completely filled with dielectric of constant `4` the force becomes `F_(2)` .If half of the distance between the charges is filled with same dielectric the force between the charges is `F_(3)` Then `F_(1):F_(2):F_(3)` is

Options

A. `16:9:4`
B. `9:36:4`
C. `4:1:2`
D. `36:9:16`

Answer

4

Explanation

`F=(1)/(4piepsilon_(0)epsilon_(r))(q_(1)q_(2))/(d^(2))`