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The inward and outward electric flux for...

The inward and outward electric flux for a closed surface unit of `N-m^(2)//C` are respectively `8xx10^(3)` and `4xx10^(3)`. Then the total charge inside the surface is [where `epsilon_(0)=` permittivity constant]

A

`4xx10^(3)`

B

`-4xx10^(3)`

C

`-(piR^(2)-piR)/(E)`

D

`-4xx10^(3)epsilon_(0)`

Text Solution

Verified by Experts

The correct Answer is:
4
`phi_(E)=(q)/(epsilon_(0))`
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Knowledge Check

  • The inward annd outward electric flux from a closed surface are respectively 8xx10^(3) and 4xx10^(3) units. Then the net charge inside the closed surface is

    A
    `-(4xx10^(3))/(epsi_(0))`coulomb
    B
    `-4xx10^(3)epsi_(0)` coulomb
    C
    `4xx10^(3)` coulomb
    D
    `(4xx10^(3))/(epsi_(0))` coulomb

  • If the electric flux entering and leaving an enclosed surface respectively is phi_1 and phi_2 then the electric charge inside the surface will he

    A
    `(phi+phi_2)epsilon_0`
    B
    `(phi_2-phi_1)epsilon_0`
    C
    `(phi_1-phi_2)epsilon_0`
    D
    `(-phi_1-phi_2)epsilon_0`

  • If the electric flux entering and leaving an enclosed surface respectively is phi_1 and phi_2 , the electric charge inside the surface will be

    A
    (a) `(phi_2-phi_1)epsilon_o`
    B
    (b) `(phi_1+phi_2)//epsilon_o`
    C
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    D
    (d) `(phi_1+phi_2)epsilon_o`

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