Two metal sphres `A` and `B` have their capacities in the ratio `3:4` they are put in contanct with each other and an amount of charge `7xx10^(-6)C` is given to the combination .Next the two spheres are spearated and kept wide the apart so that one has no elecrtrical influence on the other.The potential due to the smaller sphere at a distance of `50m` from it is

Options

A. `540V`
B. `270V`
C. `1180V`
D. zero

Answer

1

Explanation

`V_(1)=(Q)/(4piepsilon_(0))((1)/(R)-(1)/(sqrt(R^(2)+d^(2))))`
`V_(2)=((1)/(R)-(1)/(sqrt(R^(2)+d^(2))))`
`DeltaV=V_(1)-V_(2)`