A charge `+q` is fixed at each of the points `x=x_0`, `x=3x_0`, `x=5x_0`,…………`x=oo` on the x axis, and a charge `-q` is fixed at each of the points `x=2x_0`, `x=4x_0`, `x=6x_0`, …………`x=oo`. Here `x_0` is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be `Q//(4piepsilon_0r)`.Then, the potential at the origin due to the above system of

Options

A. `0`
B. `(q)/(8piepsilon_(0)x_(0)log_(e)(2))`
C. `oo`
D. `(qlog_(e)(2))/(4piepsilon_(0)x_(0))`

Answer

4

Explanation

`V=K.(Q)/(R )(V)/(2)=K.(Q)/(2)=K.(Q)/(R)`
`(1)/(2)(K.(Q)/(R))=K(Q)/(d) d=2R`
when the two conducting sphere are connected by a conducting wire ,change will flow form one sphere (having higher potential ) to other (having lower particle) till both acquire the same potential
Therfore `E=(V)/(r)`
`rArr (E_(1))/(E_(2))=(r_(2))/(r_(1))=(2)/(1)=2:1`