Home
Class 12
PHYSICS
The electric field on two sides of a lar...

The electric field on two sides of a large charged plate is shown in figure. The charge density on the plate in SI units is given by `(epsilon_0` is the permittivity of free space in SI units).

A

`2epsilon_(0)`

B

`4epsilon_(0)`

C

`10epsilon_(0)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
2

Electric field due to plate =`(sigma)/(2epsilon_(0))`
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Level 3|22 Videos
  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise NCERT based Question|14 Videos
  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Level 1|8 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NARAYNA|Exercise ADDITIONAL PROBLEMS|14 Videos
  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Comprehension type|6 Videos

Similar Questions

Explore conceptually related problems

The electric field on two sides of a thin sheet of charge is shown in the figure. The charge density on the sheet is

SI unit of in_(0) (permittivity of free space) is:

The unit of permittivity of free space epsilon_(0) is:

Define linear charge density and write its SI units.

Define volume charge density and write its SI unit.

The units of absolute permittivity of free space epsilon in S.I..are

A wire of length L= 20 cm is bent into a semicircular arc and the two equal halves of the arc are uniformly charged with charges +Q and -Q as shown in the figure. The magnitude of the charge on each half is |Q| =10^(3) epsilon_(0) , where epsilon_(0) is the permittivity of free the space. The net electric field at the center O is

Surface density of charge on a sphere of radius R in terms of electric intensity E at a distance in free space is (epsi_(0) = permittivity of free space)

The dimensions of 1/2 epsilon_(0)E^(2) (epsilon_(0)= permittivity of free space, E= electric field) is