a conducting disc of radius `R` roatates about its axis when an angular velocity `omega`.Then the potential difference between the centre of the disc and its edge is (no magnetic field is present ):

Options

A. zero
B. `(m_(e)omega^(2)R^(2))/(2e)`
C. `(m_(e)omega^(2)R^(2))/(3e)`
D. `(em_(e)omega^(2)R^(2))/(2)`

Answer

BC

Explanation

`eE=m_(e)w^(2)r`
`intEdr=(m_(e)omega^(2))/(e) int_(0)^(R)rdr V=(m_(e)omega^(2)R^(2))/(2e)`