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The potential inside a charged ball depe...

The potential inside a charged ball depends only on the distance `r` of the point form its centre according to the following relation `V=Ar^(2)+B volts` The charge density inside the ball will be

A

`-6epsilon_(0)`

B

`6epsilon_(0)`

C

`(-3epsilon_(0)A)/(r )`

D

`(-6epsilon_(0)A)/(r )`

Text Solution

Verified by Experts

The correct Answer is:
A

`V=Ar^(2)+BE=-(dV)/(dr)E=-2Ar ointvec(E)vec(ds)=(q)/(epsilon_(0))`
`-2Arxx4pir^(2)=p.(4)/(3)(pir^(3))/(epsilon_(0))rArr P=-6epsilon_(0)A`
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