In a parallel capacitor the potential difference between the plates is `V` ,A particle of mass `m` and charge `-Q` leaves the negative plate and reaches the positive plate at distance `d` in time `t` with a momentum `p` .Then

Options

A. `p=sqrt(mQV)`
B. `p=sqrt(2mQV)`
C. `t=sqrt((md^(2))/(QV)`
D. `t=sqrt((2md^(2))/(QV)`

Answer

B,D

Explanation

`(1)/(2)mv^(2)=QVrArr (p^(2))/(2m)=QVrArr p=sqrt(2mQV)`
`t=(v)/(a)=(sqrt(((2QV))/(m)))/((Q)/(m)((v))/(d)) {:.v=0+at}rArr t=sqrt((2md^(2))/(QV)`