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The sketech below show cross secion so e...

The sketech below show cross secion so equipotential surfaces between two charged.Conductors that are shwon in solid black.Some points on the wquipotenital surfaces .near the conductors are marked as `A,B,C…. .` The arrangements lies in air (Take `epsilon_(0)=8.85xx10^(-12)C^(2)//Nm^(2)]`

A positive charge is placed at `B`,When it is released:

A

no force will be exerted on it .

B

it will move towards `A`

C

it will move towards `C`

D

it will move towards `E`

Text Solution

Verified by Experts

The correct Answer is:
B
Direction of `E.F` at `B`is towards `A` will exert froce in this direction only, causing the positive charge to move .[`vec(E)` is perpendicular to equipotential surface and its direction is form high potential to low potential].
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