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The law goverening electrostatics is cou...

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that
`ointbar(E).bar(ds)=(q)/(epsilon_(0))`
where `ds` is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface.
The `SI` unit of electric flux is

A

`Vm^(-1)`

B

`vm^(2)`

C

`NC^(-1)m^(2)`

D

`NC^(-1)m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

`phi=vec(E).vec(S)=((F)/(q))s=NC^(-1)m^(2)`
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The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Consider a uniform electric field E=3xx10^(3)hat(i)NC^(-1) what is the flux thorugh a square of side 10 cm whose plane is parallel to the y-z plane?

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Gauss throrem in electrostatics states that electric flux oint(E.ds)=(q)/(epsilon_(0)) where S is the Gaussian surface ,the electric field E is due to all the charges

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