Figure shows a square current carrying loop `ABCD` of side `2m` and current` i=(1)/(2)A`. The magnetic moment `vec(M)` of the loop is

Explanation

`DA=2cos 30^(@)hat(i)-2sin30^(@)hat(k)=(-sqrt(3)hat(i)-hat(k))`
`vec(AB)=2hat(j):. vec(M)=i(vec(DA)xxvec(AB))`
`=(1)/(2)[(-sqrt(3)vec(i)-vec(k))xx(2hat(j))]`
`=-sqrt(3)k+hat(i)=(i-sqrt(3)hat(k))A-m^(2)`