If two charged particles each of charge `q` mass `m ` are connected to the ends of a rigid massless rod and is rotated about an axid passing through the centre and `_|_` to length. Then find the ratio of magnetic moment to angular momentum.

Explanation

`M=niA=2xx(q)/(t)pi((l)/(2))^(2)=2xx(qomega)/(2pi)(pil^(2))/(4)=(qomegal^(2))/(4) `
`L=2(mr^(2)omega)=2(m(l^(2))/(4)omega)=(ml^(2)omega)/(2), (M)/(L)=(q)/(2m).`