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A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil `20 cm` arranged along magnetic meridian. When a current of `0.5mA` is allowed to pass through the coil the deflection is observed to be `30^(@)`. Find the horizontal component of earth's magnetic field

Text Solution

Verified by Experts

`B=B_(H)tantheta``(mu_(0)ni)/(2rtantheta)=B_(H)`
`B_(H)=(4pixx10^(-7)xx50xx5xx10^(-4)xxsqrt(3))/(2(10^(-1))(1))`
`=5sqrt(3)xx10^(-8)T=26.35xx10^(-8)T=2.635xx10^(-7)T`
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NARAYNA-MOVING CHARGES AND MAGNETISM-EXERCISE - 4
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  2. A particle of charge +q and mass m moving under the influnce of a unif...

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  9. A circular coil of 30 turns and radius 8.0 cm carrying a current of 6....

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  10. Two Concentric circular coils X and Y of radii 16 cm and 10cm lie in ...

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  11. Toroid has a core (non-ferromagnetic) of inner radius 25 cm and outer ...

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  12. A uniform magnetic field of 1*5T is in cylindrical region of radius 10...

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  14. Two long wires carrying current I1 and I2 are arranged as shown in fig...

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  15. A current carrying loop consists of 3 identical quarter circles of rad...

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  16. A multirange current meter can be constructed by using a galvanometer ...

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  17. A long straight wire carrying current of 25A rests on a table as shown...

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  18. A 100 turn rectangular coil ABCD (in XY plane) is hung from one arm of...

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  19. A rectangular conducting loop consists of two wires on two opposite si...

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  20. An electron and a position are released from (0, 0, 0) and (0, 0, 1*5R...

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  21. Five long wires A, B, C, D and E, each carrying currentl I are arrange...

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