A long straight conductor carrying a current of `2A` is in parallel to another conductor of length `5 cm`. And carrying a current `3A`. They are separated by a distance of `10 cm`. Calculate `(a)B` due to first conductor at second conductor `(b)` the force on the short conductor.

Explanation

Given `i_(1)=2A,i_(2)=3A`
`r=10cm=10xx10^(-2)m, l_(2)=5 cm`
`(a)` `B=(mu_(0)i_(1))/(2pir)=2xx10^(-7)xx(2)/(10xx10)=4xx10^(-6)Tesla`
`(b)` `F=(mu_(0)i_(1)i_(2))/(2pir)xxl_(2)`
`=2xx10^(-7)xx(2xx3)/(10xx10^(-2))xx5xx10^(-2)=6xx10^(-7)N`