The area of the coil in a moving coil galvanometer is `15cm^(2)` and has 20 turns. The magnetic induction is `0.2T` and the couple per unit twist of the suspended wire is `10^(-6) Nm` per degree. If the deflection is `45^(@)`, the current passing through it is

Explanation

Given, `A=16cm^(2)=16xx10^(-4)m^(2)`
`B=0.2T, N=20, C=10^(-6)Nm//` degree,
`theta=45^(@)`
From, `C theta=BiAN`
`i=(C theta)/(BAN)=(10^(-6)xx45)/(0.2xx16xx10^(-4)xx20)=9.94xx10^(-1)A.`