A maximum current point `0.5mA` can be passed through a galvanometer of resistance `20Omega` . The resistance to be connected in series to convert it in the voltmeter of range `0-5V` is

Explanation

`R=G(n-),` where `n=(V)/(V_(g))`
`V=5V,V_(g)=i_(g)G=0.5xx10^(-3)xx20=10^(-2)V`
`:. N=500` and `R=20(500-1)=99980Omega`