What is the value of the shunt that passes `10%` of the main current through a galvenomenter of `99 Omega`?

Explanation

As shunt is a small resistance `S` in parallel with a galvanometer `(` of resistance `G)` as shown in figure ` (I-I_(G))S=I_(G)G`

`i.e., S=(I_(G)G)/((I-I_(G)))`
And as here, `G=99Omega` and
`I_(G)=((10)/(100))I=0.1I`
`S=(0.1Ixx99)/((I-0.1I))=(0.1)/(0.9)xx99=11Omega`