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Two wires AO and OC carry equal currents...

Two wires AO and OC carry equal currents i as shown in Fig. One end of both the wires extends to infinity. Angle AOC is `alpha`. The magnitude of magnetic field is point P on the bisector of these two wires at a distance r from point O is

A

`(mu_(0)i)/(2pir)cot((alpha)/(2))`

B

`(mu_(0)i)/(4pir)cot((alpha)/(2))`

C

`(mu_(0)i)/(2pir)((1+cos(alpha)/(2)))/(sin``((alpha)/(2)))`

D

`(mu_(0)i)/(4pir)sin((alpha)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
`B=(mu_(0))/(4pi)(I)/(a)[sin(90-theta//2)+sin90^(@)]xx2`
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Knowledge Check

  • A current carrying wire is bent in the L shapes as shown in figure. The length of both arms extend to infinity. Then, the magnetic field at O is-

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    B
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    B
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  • Two long parallel wires carry equal current i flowing in the same direction are at a distance 2d apart. The magnetic field B at a point lying on the perpendicular line joining the wires and at a distance x from the midpoint is –

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