A wire is bent in the form of a circular...

A wire is bent in the form of a circular arc with a straight portion AB. Magnetic induction at O when current flowing in the wire, is

`(mu_(0)i)/(2pir)(tanphi)`

`(mu_(0)i)/(2pir)(pi-phi)`

`(mu_(0)i)/(2pir)(pi-phi+tanphi)`

`(mu_(0)i)/(2pir)(pi-tanphi)`

Text Solution

Verified by Experts

The correct Answer is:

`B=B_(1)+B_(2),=(mu_(0)i)/(4pir)(2pi-2theta)+(mu_(0)i)/(4pid)(2sintheta)`
where `cos theta=d//r d=r cos theta`

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