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A charged particle of mass m and charge ...

A charged particle of mass `m` and charge `q` enters a magnetic field `B` with a velocity `v` at an angle `theta` with the direction of `B`. The radius fo the resulting path is

A

`(mv sin theta )/(qB)`

B

`(mv)/(q B sin theta )`

C

`(mv)/(qB)`

D

`(mv tan theta)/(qB)`

Text Solution

Verified by Experts

The correct Answer is:
A
The component`vsin theta` is perpendicular to `B`

Hence by `R=(mv_(1))/(qB),` Where is `vsin theta`. So `R=(mvsintheta)/(qB)`
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