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A potential difference of 500 V is appli...

A potential difference of 500 V is applied across a paralle plate capacitor. The separation between the plates is `2xx10^(-3)m`. The plates of the capacitor are vertical. An electron is projected vertically upwards between the plates with a velocity of `10^(5)m//a` and it moves undeflected between the plates. The magnetic field acting perpendicular to the electric field has magnitude of

A

`0" " Wb//m^(2)`

B

`5//2" " Wb//m^(2)`

C

`10^(-6)" " Wb//m^(2)`

D

`10^(5)" " Wb//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B

`evec(V)xxvec(B)=evec(B)" "impliesVB=E" "B-(E)/(V)`
Also 500 Volt `=E(2xx10^(-3)m)` .
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