A charged particle enters into a uniform magnetic field with velocity `v_(0)` perpendicular to it , the length of magnetic field is `x=sqrt(3)/(2)R`, where `R` is the radius of the circular path of the particle in the field .The magnitude of charge in velocity of the particle when it comes out of the field is

Options

A. `2v_(0)`
B. `v_(0)//2`
C. `sqrt(3)v_(0)//2`
D. `v_(0)`

Answer

D

Explanation

`sin theta=(d)/(R)=(sqrt(3))/(2)impliestheta=60^(@)`
`vec(v)_(f)=v cos hat(t)+v sin thetahat(j),vec(v)_(i)=vhat(i)`