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A current carrying loop is placed in a uniform magnetic field in four different orientations , I,ii,iii & iv arrange them in the decreasing order of potential Energy`



A

`IgtIIIgtIIgtIV`

B

`IgtIIgtIIIgtIV`

C

`IgtIVgtIIgtIII`

D

`IIIgtIVgtIIgtI`

Text Solution

Verified by Experts

The correct Answer is:
A

`U=-vec(M).vec(B)=-MB cos theta`
In case I, `theta=180^(@).U=+MB`
In case `II,theta=90^(@).U=0`
In case `III, theta =` acute`.U=+ve(` less then `+MB)`
In case `IV, " "theta =` obtuse`U=-ve" ",`
`:. IgtIIIgtIIgtIV`.
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