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A steady current i flows in a small squa...

A steady current `i` flows in a small square lopp of wire of side `L` in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let `vecmu_(1)` and `vecmu_(2)` respectively denote the magnetic moments due to the current loop before and after folding. Then

A

`vec(mu_(2))=0`

B

`vec(mu_(1))` and `vec(mu_(2))` are in the same direction

C

`|vec(mu_(1))|//|vec(mu_(2))|=sqrt(2)`

D

`|vec(mu_(1))|//|vec(mu_(2))|=(1//sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`|vec(mu)_(1)|=IA,|vec(mu)_(2)|=I(sqrt(2)A)`
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NARAYNA-MOVING CHARGES AND MAGNETISM-LEVEL-VI (SINGLE ANSWER QUESTION)
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