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A horizontal straight conductor of mass ...

A horizontal straight conductor of mass m and length l is placed in a uniform vertical magnetic firled of magnitude B. An amount of charge Q passes through the rod in a very short time such that the conductor begins to move only after all the charge has passed throught is. Its initial velocity will be

A

`BQlm`

B

`(BQ)/(lm)`

C

`(BQl)/(m)`

D

`(Bl)/(mQ)`

Text Solution

Verified by Experts

The correct Answer is:
C
The ampere force on the conductor is `F=Bil`. The impulse given by this force to the conductor is `J=int Fdt=B1int i dt=BiQ`
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