Home
Class 12
PHYSICS
A proton and an alpha- particle enter a ...

A proton and an `alpha-` particle enter a uniform magnetic field at right angles to the field with same speed. The ratio of the periods of `alpha-` particle and proton is

A

`1:1`

B

`1:4`

C

`1:2`

D

`2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the periods of an alpha particle and a proton when they enter a uniform magnetic field at right angles with the same speed. ### Step-by-Step Solution: 1. **Understanding the Motion in a Magnetic Field**: When a charged particle moves in a magnetic field, it experiences a centripetal force that keeps it moving in a circular path. The radius \( r \) of the circular path is given by the formula: \[ r = \frac{mv}{qB} \] where \( m \) is the mass of the particle, \( v \) is its velocity, \( q \) is the charge, and \( B \) is the magnetic field strength. 2. **Finding the Time Period**: The time period \( T \) of the circular motion is the time taken to complete one full circle. The circumference of the circle is \( 2\pi r \), and the time period can be expressed as: \[ T = \frac{\text{Circumference}}{\text{Velocity}} = \frac{2\pi r}{v} \] Substituting the expression for \( r \): \[ T = \frac{2\pi \left( \frac{mv}{qB} \right)}{v} = \frac{2\pi m}{qB} \] 3. **Calculating the Time Periods for Proton and Alpha Particle**: - For the proton: \[ T_p = \frac{2\pi m_p}{q_p B} \] - For the alpha particle (which has twice the charge and four times the mass of a proton): \[ T_{\alpha} = \frac{2\pi m_{\alpha}}{q_{\alpha} B} = \frac{2\pi (4m_p)}{(2q_p) B} = \frac{4\pi m_p}{2q_p B} = \frac{2\pi m_p}{q_p B} \] 4. **Finding the Ratio of Time Periods**: Now, we can find the ratio of the time periods of the alpha particle to the proton: \[ \frac{T_{\alpha}}{T_p} = \frac{\frac{2\pi m_{\alpha}}{q_{\alpha} B}}{\frac{2\pi m_p}{q_p B}} = \frac{m_{\alpha}/q_{\alpha}}{m_p/q_p} \] Substituting the values: \[ = \frac{4m_p / 2q_p}{m_p / q_p} = \frac{4}{2} = 2 \] ### Final Answer: The ratio of the periods of the alpha particle to the proton is: \[ \frac{T_{\alpha}}{T_p} = 2 \]

To solve the problem, we need to find the ratio of the periods of an alpha particle and a proton when they enter a uniform magnetic field at right angles with the same speed. ### Step-by-Step Solution: 1. **Understanding the Motion in a Magnetic Field**: When a charged particle moves in a magnetic field, it experiences a centripetal force that keeps it moving in a circular path. The radius \( r \) of the circular path is given by the formula: \[ r = \frac{mv}{qB} ...
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise Level -II (H.W)|37 Videos
  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise ILLUSTRATION|58 Videos
  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise LEVEL-VI (SINGLE ANSWER QUESTION)|81 Videos
  • MAGNETISM AND MATTER

    NARAYNA|Exercise EXERCISE - 4 (SINGLE ANSWER TYPE QUESTION)|17 Videos
  • NUCLEAR PHYSICS

    NARAYNA|Exercise LEVEL-II-(H.W)|9 Videos

Similar Questions

Explore conceptually related problems

An electron and a proton enter a magnetic field at right angles to the field with the same kinetic energy

A proton and an a-particle enter in a uniform magnetic field perpendicularly with same speed. The will b ratio of time periods of both particle (T_(p)/(T_(alpha)) will be

Statement 1: If a proton and an alpha -particle enter a uniform magnetic field perpendicularly with the same speed, the time period of revolution of alpha -particle is double than that of proton. Statement 2: In a magnetic field, the period of revolution of a charged particle is directly proportional to the mass of the particle and inversely proprotional to the charge of particle.

A proton and an alpha -particles enters in a uniform magnetic field with same velocity, then ratio of the radii of path describe by them

A proton and helium nucleus are shot into a magnetic field at right angles to the field with same kinetic energy. Then the ratio of their radii is

A proton and an alpha particle both enters a region of uniform magnetic field B, moving at right angles to the field B. If the radius of circular orbits for both the particles is equal and the kinetic energy acquired by proton is 1 MeV , the energy acquired by the alpha particles will be :

A protn and an alpha particle enter into a uniform magnetic field with the same velocity. The period of rotation of the alpha particle will be

NARAYNA-MOVING CHARGES AND MAGNETISM-Level =I (H.W)
  1. A circular coil of wire "n" turns has a radius "r" and carries a curre...

    Text Solution

    |

  2. A long solenoid has 20 turns per cm and carries a current i. the magne...

    Text Solution

    |

  3. A proton and an alpha- particle enter a uniform magnetic field at righ...

    Text Solution

    |

  4. A proton takes 10^(-12)s to complete one revolution in uniform magneti...

    Text Solution

    |

  5. A charged particle , having charge q accelerated through a potential d...

    Text Solution

    |

  6. A proton moving with a velocity of 2xx10^(6)ms^(-1) describes circle o...

    Text Solution

    |

  7. A particle of charge 16xx10^(-18) coulomb moving with velocity 10m//s ...

    Text Solution

    |

  8. A proton is rotating along a circular path with kinetic energy K in a...

    Text Solution

    |

  9. In a cyclotron , if the frequency of proton is 5MHz, the magnetic fiel...

    Text Solution

    |

  10. A cyclotron's oscillator frequency is 10 MHz . The operating magnetic ...

    Text Solution

    |

  11. A straight wire of length 0.5 metre and carrying a current of 1.2 ampe...

    Text Solution

    |

  12. Two parallel conductor carrying 5A each , repel with a force of 0.25Nm...

    Text Solution

    |

  13. Two straight parallel wires carry currents of 200 mA and 1A in opposit...

    Text Solution

    |

  14. Two long parallel copper wires carry currents of 5 A each in opposite ...

    Text Solution

    |

  15. A rectangular coil of wire of area 400cm^(2) contain 500 turns. It is ...

    Text Solution

    |

  16. A rectangular coil of wire carrying a current is suspended in a unifor...

    Text Solution

    |

  17. A vertical rectangular coil of sides 5 cm xx 2 cm has 10 turns and car...

    Text Solution

    |

  18. The coil in a MCG has an area of 4cm^(2) and 500 turns. The intensity ...

    Text Solution

    |

  19. The area of the coil in a moving coil galvanometer is 15cm^(2) and has...

    Text Solution

    |

  20. The sensitivity of a galvanometer of resistance 990Omega is increased ...

    Text Solution

    |