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A proton takes 10^(-12)s to complete one...

A proton takes `10^(-12)s` to complete one revolution in uniform magnetic field. The time taken in another orbit of double the radius in the same field is

A

`0.5xx10^(-12)sec`

B

`2xx10^(-12)sec`

C

`4xx10^(-12)sec`

D

`10^(-12)sec`

Text Solution

Verified by Experts

The correct Answer is:
4
`(T_(1))/(T_(2))=(m_(1))/(m_(2))xx(q_(2))/(q_(1))`
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