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A proton moving with a velocity of 2xx10...

A proton moving with a velocity of `2xx10^(6)ms^(-1)` describes circle of radius `R` in a magnetic field. The speed of an `alpha-` particle to describe a circle of same radius in the same magnitude field is

A

`1xx10^(6)m//s`

B

`2xx10^(6)m//s`

C

`4xx10^(6)m//s`

D

`8xx10^(6)m//s`

Text Solution

Verified by Experts

The correct Answer is:
1
`(V_(1))/(V_(2))=(q_(1))/(q_(2))xx(m_(2))/(m_(1))`
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