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A rectangular coil of wire carrying a cu...

A rectangular coil of wire carrying a current is suspended in a uniform magnetic field. The plane of the coil is making an angle of `30^(@)` with the direction of the field and the torque experienced by it is `tau_(1)` and when the plane of the coil is making an angle of `60^(@)` with the direction of the field the torque experienced by it is `tau_(2)`. Then the ratio `tau_(1):tau_(2)` is

A

`1:sqrt(3)`

B

`sqrt(3):1`

C

`1:3`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
2
`tau = BAIncos theta`
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