A galvanometer has a resistance of 49Ome...

A galvanometer has a resistance of `49Omega`.If `2%` of the main current is to be passed through the meter, The value of the shunt will be

`2 Omega`

`1 Omega`

`(1)/(2)Omega`

`(1)/(4)Omega`

Text Solution

Verified by Experts

The correct Answer is:

`i_(g)=(iS)/(G+S)`

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