A galvanometer of internal resistance 10...

A galvanometer of internal resistance `100 Omega` has a full scale deflection current of `1mA`. To convert it into a voltmeter of range `0-10V`, the resistance to be connected is

`9000 Omega` in Series

`10,000 Omega` in Series

`9,900 Omega` in Series

`9,800 Omega` in Series

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The correct Answer is:

`R=(V)/(i_(g))-G`

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