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Due to a straight vertical current carry...

Due to a straight vertical current carrying conductor, a null point occurred at P on east of the conductor. The net magnetic induction at a point `'Q'` which is at same distance on north of the conductor is

A

0

B

`sqrt(2)B_(H)`

C

`B_(H)`

D

`sqrt(2)B_(H)`

Text Solution

Verified by Experts

The correct Answer is:
4
`R=sqrt(B^(2)+B_(H)^(2))=sqrt(B_(H)^(2)+B_(H)^(2))=sqrt(2)B_(H)`
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