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An electron is shot in steady electric a...

An electron is shot in steady electric and magnetic field E and magnetic field B mutually perpendicular. The magnitude of E is `1` volt `//` cm and that of B is 2 tesla. Now it happens that the Lorentz ( Magnetic ) force cancels with the electro static force on the electron, then the velocity of the electron is

A

`50ms^(-1)`

B

`2 cm^(-1)`

C

`0.5cm^(-1)`

D

`200ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
1
`r=(mv)/(Bq)`
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