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A beam of protons with a velocity of 4 X...

A beam of protons with a velocity of `4 X 10 ^5 ms^(-1)` enters a uniform magnetic field of 0.3 T. The velocity makes an angle of `60^@` with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

A

`4.7m`

B

`0.47m`

C

`0.047m`

D

`0.0047m`

Text Solution

Verified by Experts

The correct Answer is:
3
`p=v cos theta xxT,T=(2pir)/(v sin theta)`
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