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A flip coil consits of N turns of circu...

A flip coil consits of `N` turns of circular coils which lie in a uniform magnetic field. Plane of the coils is perpendicular to the magnetic field as shown in figure. The coil is connected to a current integrator which measures the total charge passing through it. The coil is turned through `180^(@)` about the diameter. The charge passing through the coil is

A

`(NBA)/(R )`

B

`(sqrt(3) NBA)/(2R)`

C

`(NBA)/(sqrt(2)A)`

D

`(2NBA)/(R )`

Text Solution

Verified by Experts

The correct Answer is:
D
Initial flux through the coil, `phi_(Bi) = +NBA`
Final flux through the coil, `phi_(Bi) = +NBA`
When the coil is turned through `180^(@)` its flux reverses, the angle between magntic field and area vector is reversed.
`Delta phi_(B) = phi_(Bf) - phi_(Bi) = -NBA-(NBA) = -2NBA`
`Q = (Delta phi_(B))/(R ) = (2NBA)/(R )`
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