To measure the field `'B'` between the poles of an electronmagnet, a small test loop of area `1 cm^(2)`, resistance `10 Omega` and `20` turns is pulled out of it. A galvanometer shows that a total charge `2mu C` passed through the loop. The value of `'B'` is

Options

A. `0.001 T`
B. `0.01 T`
C. `0.1 T`
D. `1.0 T`

Answer

B

Explanation

`q = (e )/(R ) dt = ((B_(1)-B_(2))NA)/(R )`
`2 mu c = ((B-0)20 xx 10^(-4))/(10) = 0.01T`